Cubs, Indians battle for World Series title in 37th Game 7 in history

The Chicago Cubs and the Cleveland Indians at Game Six.
(Image credit: Jamie Squire/Getty Images)

The Chicago Cubs have survived two elimination games in a row to force Game 7 of the World Series against the Cleveland Indians, just the 37th-ever do-or-die game in World Series history. Wednesday night's Game 7, set to take place at Ohio's Progressive Field, will either way end a lengthy championship drought: The Indians have gone 68 years without the Commissioner's Trophy, while it's been 108 years for the Cubs.

Chicago will start Kyle Hendricks on the mound, who will have one more day of rest than Cleveland's ace, Corey Kluber. Kluber will have the unenviable task of facing the Cubs' hard-hitting lineup of batters, but the Indians pitcher boasts 35 strikeouts and three runs allowed over 30-and-a-half innings and five starts this postseason.

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Jeva Lange

Jeva Lange was the executive editor at TheWeek.com. She formerly served as The Week's deputy editor and culture critic. She is also a contributor to Screen Slate, and her writing has appeared in The New York Daily News, The Awl, Vice, and Gothamist, among other publications. Jeva lives in New York City. Follow her on Twitter.